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W2.1 Energy Use in Transportation

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Key points

  • Moving at constant speed = continuously giving energy away: push the medium aside (Drag), push air down (Lift), deform tyres (Rolling resistance), throw away 12Mv2\frac12 Mv^2 at every stop (Braking power)
  • Ptot=Pdrag+Plift+Proll+PbrakeP_{tot} = P_{drag} + P_{lift} + P_{roll} + P_{brake}; only the terms that apply to the medium (water / air / land)
  • Energy per distance =P/v= P/v = total resistive force → [J/m]=[N][\text{J/m}] = [\text{N}]
  • Ships: weight carried by Buoyancy. Archimedes’ principle → draught XX → submerged area XWXW → water drag (air drag ≈ 1%)
  • Compare modes per cargo or person and distance: kWh/(tonne·100 km), kWh/(person·100 km)
  • Real vehicles: engine efficiency ~25%, start-up losses, climate control, accessories → car 40–120 kWh/100 km (lecture, source K. Blok)

Chains

  • Ship: Buoyancy. Archimedes’ principle → XX → A=XWA = XW → Drag → PP → E/d=P/vE/d = P/v → per tonne or person → fuel mass (η\eta, energy density)
  • Plane: Lift (∝1/v\propto 1/v) + Drag (∝v3\propto v^3) → optimal speed
  • Car / bus / train: Drag + Rolling resistance + Braking power

Calculation pattern (HW)

  1. PusedP_{used} = load factor × PengineP_{engine} (HW: 80%, car 60%)
  2. E/d=Pused/vE/d = P_{used}/v → kWh/km (kWkm/h\frac{\text{kW}}{\text{km/h}}) → ×100
  3. ÷ cargo mass (tonnes) or ÷ persons (full capacity)
  4. Fuel: mfuel=Emechη efuelm_{fuel} = \frac{E_{mech}}{\eta\, e_{fuel}} (HW: gasoline 12.4 kWh/kg, η\eta = 25%)
Typical traps
  • Divide by the cargo (load), not the vehicle’s own mass; per person: full capacity unless told otherwise
  • Engine power given = maximum → load factor first
  • knots → km/h (1 knot = 1.85 km/h); bhp → kW (1 bhp ≈ 0.746 kW, not given in HW)
  • km/h → m/s (÷ 3.6) before cubing vv
  • “weight MM = 2000 kg” in exam text = mass [kg]; weight as a force = MgMg [N]. In ship tasks WW = width → write FGF_G, FBF_B
  • Model gives mechanical power; fuel needs ÷ η\eta
  • Nov 2023 2b answer key: 91.4 → recalculated 93.3 kWh/(person·100 km) (slip in key)
“Derive …” checklist
  1. Write the target (Elift/dE_{lift}/d, Efloat/dE_{float}/d, …)
  2. Read the sentence right before it: the hint is there (“power = force × velocity”, “first derive D”)
  3. Use only the formulas and symbols given in the question (not the formula-sheet version of a similar thing)
  4. Check what the next sub-question needs (a number → the expression must contain given values)
  5. Transport: E/dE/d = a force

Order-of-magnitude check (lecture, K. Blok)

ModekWh/(person·km)
Passenger car0.44
City bus0.27
Local train/tram0.23
Intercity train0.14
High-speed train0.3
Aircraft0.55
(×100 → kWh/(person·100 km))
Exam
  • Nov 2023 Task 2 (17 pt): hydrofoil water-taxi
  • a–b floating: Buoyancy. Archimedes’ principle → draught → Drag → E/d∝M/LE/d \propto M/L; 93.3 kWh/(person·100 km)
  • c–e flying: given Flift=12CliftAwingρwv2F_{lift} = \frac12 C_{lift} A_{wing}\rho_w v^2 (coefficient model, not the formula-sheet plane formula); vminv_{min} when FB=0F_B = 0 → Flift=MgF_{lift} = Mg; exam sets Elift/d=Flift=MgE_{lift}/d = F_{lift} = Mg; 68 kWh/(person·100 km) → 27% saved (lift ≈ 99% of it, wing drag ≈ 1%)
  • Oct 2025 MCQ 5.11: ship at 80% of vv over A→B → E∝v2E \propto v^2 → 36% saved
  • Oct 2025 MCQ 5.12: chain efficiency e-car vs combustion car → Energy Efficiency (W1.6)
  • Old SET3013: Nov 2016 T1 (container ship + kite), Jan 2018 T1 (A380 lift & drag), Nov 2018 T4 (cargo by boat), Nov 2019 T2 (tanker vs pipeline)

Concepts

  • Drag
  • Lift
  • Rolling resistance
  • Braking power
  • Buoyancy. Archimedes’ principle