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RE

Units & conversions

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Not on the formula sheet.

Power vs energy

WW is rate (power), WhWh is amount (energy). 1 W=1 J/s1 kWh=3.6 MJ1\ \text{W} = 1\ \text{J/s} \qquad 1\ \text{kWh} = 3.6\ \text{MJ}

SI building blocks

UnitQuantityFrom=
NforceF=maF = makg⋅m/s2\text{kg·m/s}^2
Papressurep=F/Ap = F/AN/m2=kg/(m⋅s2)\text{N/m}^2 = \text{kg/(m·s}^2)
JenergyE=F⋅dE = F \cdot dN⋅m\text{N·m}
WpowerP=E/t=F⋅vP = E/t = F \cdot vJ/s\text{J/s}

Other conversions

  • 1 ktoe≈11.6 GWh≈42 TJ1\ \text{ktoe} \approx 11.6\ \text{GWh} \approx 42\ \text{TJ} (1 tonne of oil ≈ 12 MWh); usually given in the exam, check for typos
  • World average energy use ≈ 65 kWh/(person·day) (2018, Introduction lecture; 1998: 53) → benchmark for “compare to the global average” (not given in the exam)
  • 1 ppm=1000 ppb1\ \text{ppm} = 1000\ \text{ppb}
  • 1 m3=1000 L1\ \text{m}^3 = 1000\ \text{L}
  • T[K]=T[°C]+273T[\text{K}] = T[°\text{C}] + 273; a difference ΔT\Delta T is the same in °C and K
Unit check (atmosphere mass, HW 1A)

M=pAg→kg/(m⋅s2)⋅m2m/s2=kgM = \frac{pA}{g} \rightarrow \frac{\text{kg/(m·s}^2)\cdot\text{m}^2}{\text{m/s}^2} = \text{kg} ✓

Related: Mole and Avogadro constant, Flow = driving force ÷ resistance